DC = 6
So
CE + DE = 6
2DE + DE = 6
3DE = 6
DE = 2
Since DE is parallel to AB in triangle FAB..then
AB /AF = DE /DF
6 / [ AD + DF ] = 2 / DF
6 / [ 6 + DF] = 2 /DF
6DF = 2 [ 6 + DF]
6DF = 12 + 2DF
4DF = 12
DF = 3
So angle EDF is right and its area = 1/2 * (DE * DF) = (1/2)(2 * 3) = 3 units^2