if an object was 2 kilograms and was travelling at the speed of 70 mile per hour then how high will the object be placed?
+130515 I think the questioner wants to know at what height was an object dropped if, upon impact, it was traveling at 70mph = about 102.66 ft/s
The weight of the object is irrelevent........the "formula" we need is this one :
[vf]^2 = [vi]^2 + 2 * a * d where vf is the final velocity, vi is the initial velocity (0), "a" is the acceleration due to gravity [32ft/s^2] and "d" is the distance it falls [ in feet]......so we have
[102.66ft/s]^2 = 0 + 2(32ft/s^2) * d
10540.44 [ft/s]^2 = 64 ft/s^2 *d dividing both sides by 64 ft/s^2....we have
[10540.44 / 64 ] ft = d = about 164.69 ft.
