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How do you simplify [(-4x^2)^2]/[(8y^6)^1/3]

Olivia3.141592654 Jan 14, 2016

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Best Answer

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[(-4x^2)^2]/[(8y^6)^1/3] =

( [-4]^2 * [ x^2]^2) / ( 8^(1/3) * [y^6]^(1/3) ] =

[16 x^4 ] / [2 y ^2 ] =

[8 x^4] / [ y^2]

CPhill Jan 14, 2016

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+129852

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Best Answer

[(-4x^2)^2]/[(8y^6)^1/3] =

( [-4]^2 * [ x^2]^2) / ( 8^(1/3) * [y^6]^(1/3) ] =

[16 x^4 ] / [2 y ^2 ] =

[8 x^4] / [ y^2]

CPhill Jan 14, 2016

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Thanks, Chris!!!

Olivia3.141592654 Jan 14, 2016

+129852

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No prob....OP !!!!

CPhill Jan 14, 2016

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