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Simplifiy (3-2i)^2

 Dec 10, 2014

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 #2
avatar+118609 
+10

Sassini is right but it is not finished

$${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$$ 

 

=   $${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,-\,}}{\mathtt{4}}$$

 

=  $${\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{12}}{i}$$

 Dec 11, 2014
 #1
avatar+752 
+10

$${\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{2}}{i}\right)}^{{\mathtt{2}}}$$

$${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$$

.
 Dec 10, 2014
 #2
avatar+118609 
+10
Best Answer

Sassini is right but it is not finished

$${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$$ 

 

=   $${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,-\,}}{\mathtt{4}}$$

 

=  $${\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{12}}{i}$$

Melody Dec 11, 2014

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