Simplifiy (3-2i)^2

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689

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Simplifiy (3-2i)^2

Guest Dec 10, 2014

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+10

Best Answer

Sassini is right but it is not finished

${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$

= ${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,-\,}}{\mathtt{4}}$

= ${\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{12}}{i}$

Melody Dec 11, 2014

Melody · Answer 1 · 2014-12-11T03:31:48

Sassini is right but it is not finished

${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$

= ${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,-\,}}{\mathtt{4}}$

= ${\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{12}}{i}$

Sasini · Answer 2 · 2014-12-10T03:01:46

${\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{2}}{i}\right)}^{{\mathtt{2}}}$

${\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{12}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\left[{{i}}^{{\mathtt{2}}}\right]$

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