+118725 simplify: (-3x^2)+12x+96 / (-x^3)+(6x^2)+96x+1
$$\frac{-3x^2+12x+96}{-x^3+6x^2+96x+1}\\\\
\frac{-3(x^2-4x-32)}{-(x^3-6x^2-96x-1)}\\\\$$
NOW FRAC IS NOT DISPLAYING PROPERLY EITHER!
\frac{-3(x^2-4x-32)}{-(x^3-6x^2-96x-1)}\\\\ THIS WAS MY INPUT FOR THE LAST LINE
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I am sorry the forum has just been overhauled and very little is working properly. So it is hard to show you.
anyway, factorise out the -3 on the top and the -1 on the bottom and cancel the minus signs.
You end up with 3(x-8)(x+4) on the top and $$x^3-6x^2-96x-1$$ on the bottom
The only way this can be simplified further is if (x-8) or (x+4) is a factor of the denominator.
Using factor theorum; If (x-8) is a factor then x=8 will make the expression =0
$${{\mathtt{8}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{{\mathtt{8}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{96}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{1}}$$ = -641 so (x-8) is not a factor
substitute in x=-4 and see if that works. If it does you can cancel the (x+4) factors but I don't think that it does which means that it cannot be simplified any further.
If this site wasn't so frustrating I would help more. sorry.
