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Simplify (1+3+5+...+199)/(2+4+6+...+200)

 Feb 9, 2018
 #1
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We have  [ 199 -1] / 2  + 1  =  100 terms at the top

 

And  the sum of the terms at the top can be written as

 

( 1 + 199) (100) / 2   =    200 * 100 /2  =  200 * 50

 

And we have  [ 200 - 2 ] / 2  +1     =  198/2 +  1   =  99 + 1  = 100 terms on the bottom

 

And the sum of these terms is    ( 200 + 2) (100/2)  =  202 * 50

 

So we have

 

[  200 * 50  ] / [ 202 * 50]  =  200 / 202  =   100 / 101

 

 

cool cool cool

 Feb 9, 2018

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