simplify 12((3x-4)/(3)-(3-4x)/(4)-(6-2x)/(6))

12((3x-4)/(3)-(3-4x)/(4)-(6-2x)/(6))

$=\,12(\frac{3x-4}{3}-\frac{3-4x}{4}-\frac{6-2x}{6})$

$=\,\frac{(12)(3x-4)}{3}-\frac{(12)(3-4x)}{4}-\frac{(12)(6-2x)}{6} \\~\\ =\,\frac{(4)(3x-4)}{1}-\frac{(3)(3-4x)}{1}-\frac{(2)(6-2x)}{1} \\~\\ =\,(4)(3x-4)-(3)(3-4x)-(2)(6-2x) \\~\\ =\,12x-16 - 9+12x -12+4x \\~\\ =\,28x-37$            Reduce the fractions.