I know (2^(2+4)-2(2^n))/(2(2^(n+3)) is hard to compute, sorry, but please help!

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Simplify: (2^(2+4)-2(2^n))/(2(2^(n+3)). Express your answer as a common fraction.

APatel Jan 17, 2019

edited by APatel Jan 17, 2019

CPhill · Answer 1 · 2019-01-17T03:08:54

(2^(2+4)-2(2^n))/(2(2^(n+3)). =

[ 2^6 - 2(2^n ] / [ 2 * 2^(n + 3) ] =

[ 2^6 - 2^(n + 1) ] / [ 2^(n + 4) ] =

[ 64 - 2^(n + 1) ] / [2 ^(n + 4) ] =

[ 2 * 2^5 - 2 * 2^n ] / [ 2* 2^(n + 3) ] =

[ 2^5 - 2^n ] / [ 2^(n + 3) ] =

[32 - 2^n ] / [ 8 * 2^n ]

This is all we can do