+118724 Hi GoldenLeaf, thanks for answering, we like everyone to get involved
Oh and welcome to Web2.0calc forum. We hope you like it her.
Unfortunately what you have done is not correct because the 2 is not meant to be raised to the power of 3.
$$2(-3x^2y^3)^3\\\\
=2\times ((-1)^3\times 3^3\times (x^2)^3\times (y^3)^3)\\\\
=2\times(-1\times 27\times x^6 y^9)\\\\
=-54x^6y^9$$
+1006 Distribute the 2 on the outside of the parenthesis first.
(-6x^2y^3)^3
Past that, I'm not entirely sure. It would make sense to just make is -6x^2y^3^3, which is (simplifying the 3^3) -6x^2y^27
+118724 Hi GoldenLeaf, thanks for answering, we like everyone to get involved
Oh and welcome to Web2.0calc forum. We hope you like it her.
Unfortunately what you have done is not correct because the 2 is not meant to be raised to the power of 3.
$$2(-3x^2y^3)^3\\\\
=2\times ((-1)^3\times 3^3\times (x^2)^3\times (y^3)^3)\\\\
=2\times(-1\times 27\times x^6 y^9)\\\\
=-54x^6y^9$$
