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avatar+307 

More help please??

 

Simplify.

 

4x^2+2x

-----------

x^2+x−2

------------------------

8x^2+4x

--------------

3x^2+10x+8

 

3x+4/2(x−1)

3x+4/2(x+1)

3x+4/2x(x−1)

3x−4/2(x−1)

 

Thank you!

 Nov 28, 2018
 #1
avatar+99617 
+2

Inverting the fraction in the denominator and multiplying, we have

 

(4x^2 + 2x) /  ( x^2 + x - 2)   *    (3x^2 + 10x + 8) / (8x^2 + x)   =

 

( 4x^2 + 2x) (3x^2 + 10x + 8)

________________________            factor each term

(x^2 + x - 2) (8x^2 + 4x)

 

 

(2x) ( 2x + 1) (3x + 4) (x + 2)

_______________________         "cancel" where possible

(x +2) (x - 1) (4x) (2x + 1) 

 

 

(3x + 4)

__________   =    the first answer

2(x - 1)

 

 

cool cool cool

 Nov 28, 2018
 #2
avatar+307 
0

Thank you so much for helping me out with this one and explaining the process to me!!

PhoenixForever  Nov 29, 2018

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