More help please??
Simplify.
4x^2+2x
-----------
x^2+x−2
------------------------
8x^2+4x
--------------
3x^2+10x+8
3x+4/2(x−1)
3x+4/2(x+1)
3x+4/2x(x−1)
3x−4/2(x−1)
Thank you!
Inverting the fraction in the denominator and multiplying, we have
(4x^2 + 2x) / ( x^2 + x - 2) * (3x^2 + 10x + 8) / (8x^2 + x) =
( 4x^2 + 2x) (3x^2 + 10x + 8)
________________________ factor each term
(x^2 + x - 2) (8x^2 + 4x)
(2x) ( 2x + 1) (3x + 4) (x + 2)
_______________________ "cancel" where possible
(x +2) (x - 1) (4x) (2x + 1)
(3x + 4)
__________ = the first answer
2(x - 1)
Thank you so much for helping me out with this one and explaining the process to me!!