#1**+1 **

I'm not exactly sure if I'm doing correctly, but I'll try my best.

First off, let's note that \(a^x \cdot a^y = a^{x+y}\).

Using this logic, we would have \(q^{\frac{5}{3}}p^{\frac{5}{4}}r^{\frac{31}{12}}\).

In order to not have fractional exponents, we would have to put these into radical form.

Note that \(a^{x/y} = \sqrt[y]{a^x}\).

We would get \(\sqrt[3]{q^5} \cdot \sqrt[4]{p^5} \cdot \sqrt[12]{r^{31}} \).

I hope I answered your question!

Thanks! :)

NotThatSmart May 31, 2024

#1**+1 **

Best Answer

I'm not exactly sure if I'm doing correctly, but I'll try my best.

First off, let's note that \(a^x \cdot a^y = a^{x+y}\).

Using this logic, we would have \(q^{\frac{5}{3}}p^{\frac{5}{4}}r^{\frac{31}{12}}\).

In order to not have fractional exponents, we would have to put these into radical form.

Note that \(a^{x/y} = \sqrt[y]{a^x}\).

We would get \(\sqrt[3]{q^5} \cdot \sqrt[4]{p^5} \cdot \sqrt[12]{r^{31}} \).

I hope I answered your question!

Thanks! :)

NotThatSmart May 31, 2024