+0

# simplify exponents with no fractional exponents in the denominator

0
3
1
+4

qp^_3/4r^5/4*p^_1/2q^2/3r^_4/3

need help!

May 30, 2024

#1
+806
+1

I'm not exactly sure if I'm doing correctly, but I'll try my best.

First off, let's note that $$a^x \cdot a^y = a^{x+y}$$

Using this logic, we would have $$q^{\frac{5}{3}}p^{\frac{5}{4}}r^{\frac{31}{12}}$$

In order to not have fractional exponents, we would have to put these into radical form.

Note that $$a^{x/y} = \sqrt[y]{a^x}$$.

We would get $$\sqrt[3]{q^5} \cdot \sqrt[4]{p^5} \cdot \sqrt[12]{r^{31}}$$.

Thanks! :)

May 31, 2024

#1
+806
+1

I'm not exactly sure if I'm doing correctly, but I'll try my best.

First off, let's note that $$a^x \cdot a^y = a^{x+y}$$

Using this logic, we would have $$q^{\frac{5}{3}}p^{\frac{5}{4}}r^{\frac{31}{12}}$$

In order to not have fractional exponents, we would have to put these into radical form.

Note that $$a^{x/y} = \sqrt[y]{a^x}$$.

We would get $$\sqrt[3]{q^5} \cdot \sqrt[4]{p^5} \cdot \sqrt[12]{r^{31}}$$.