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deleted.

 Jun 12, 2019
edited by sinclairdragon428  Nov 20, 2019
edited by sinclairdragon428  Nov 21, 2019
 #1
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\(\frac{2m+8}{3}-\frac{2-m}{3}\ =\ \frac{(2m+8)-(2-m)}{3}\ =\ \frac{2m\,+\,8\,-\,2\,+\,m}{3}\ =\ \frac{3m+6}{3}\,=\,\frac{3m}{3}+\frac63\ =\ m+2\)_

 Jun 12, 2019
 #2
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Thanks!

sinclairdragon428  Jun 12, 2019

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