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Question

0

975

2

+379

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edited by sinclairdragon428 Nov 20, 2019
edited by sinclairdragon428 Nov 21, 2019

hectictar · Answer 1 · 2019-06-12T01:09:34

$\frac{2m+8}{3}-\frac{2-m}{3}\ =\ \frac{(2m+8)-(2-m)}{3}\ =\ \frac{2m\,+\,8\,-\,2\,+\,m}{3}\ =\ \frac{3m+6}{3}\,=\,\frac{3m}{3}+\frac63\ =\ m+2$ _

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