deleted.

\(\frac{2m+8}{3}-\frac{2-m}{3}\ =\ \frac{(2m+8)-(2-m)}{3}\ =\ \frac{2m\,+\,8\,-\,2\,+\,m}{3}\ =\ \frac{3m+6}{3}\,=\,\frac{3m}{3}+\frac63\ =\ m+2\)_