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(n+3)! / (n+1)!

 Oct 5, 2016
 #1
avatar+129840 
0

[ n + 3] !   / [ n + 1] !   =

 

[ (n + 3) (n + 2) (n + 1) * .......* 1]   / [ (n + 1) * .......* 1  ]  =

 

[ ( n + 3) (n + 2)  ]  = 

 

n^2 + 5n + 6

 

 

 

 

cool cool cool

 Oct 5, 2016
 #2
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0

  (n+3)! / (n+1)! = (n+2) (n+3)

 Oct 5, 2016

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