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Squareroot of (80a^4b^5) where a>0 & b>0

 Jul 10, 2014

Best Answer 

 #1
avatar+130518 
+5

I think you mean you want to simplify this.  (There is no denominator!!!)....So we have...

√(80a^4b^5) = √(16* 5*a^4*b^5) = 4a2b2√(5b)

 

  

 Jul 10, 2014
 #1
avatar+130518 
+5
Best Answer

I think you mean you want to simplify this.  (There is no denominator!!!)....So we have...

√(80a^4b^5) = √(16* 5*a^4*b^5) = 4a2b2√(5b)

 

  

CPhill Jul 10, 2014

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