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1. Simplify sqrt108x^5y^8

2. Simplify (sqrt3) - (sqrt2)/(sqrt3) + (sqrt2)

3. Rewrite 32^5/3 as a radical expression and then simplify

brandyscott29  Feb 28, 2017
 #1
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1. Simplify sqrt108x^5y^8

 

I'm assuming that x and y are positive

 

√[ 108 x^5 y^8]  =  √[36 *3 * x^4 * x * y^8 ] =  6x^2y^4 √ [ 3x]

 

 

2. Simplify (sqrt3) - (sqrt2)/(sqrt3) + (sqrt2)

 

[ √3 - √2 ] / [ √3 + √2 ]       multiply top/bottom by √3 - √2

 

 ( [ √3 - √2 ] [ √3 - √2 ] ) / ( [ √3 + √2 ] [ √3 - √2 ] )   =

 

( 3 - 2√6 + 2 ) / ( 3  - 2)  =

 

[ 5 - 2√6 ] / 1  =

 

[ 5 - 2√6 ]

 

 

 

3. Rewrite 32^5/3 as a radical expression and then simplify

 

 

32^(5/3)   =   3√[ 32^5] = 3√[ (2^5)^5]  =  3√[ 2^25]   = 2^8* 3√2  = 256 3√2

 

 

cool cool cool

CPhill  Feb 28, 2017

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