simplify the expression "the square root of x^10 times the square root of x^4" completely
In the form of a formula this is:
√x10×√x4
Some things to consider:
Ax * Ay = Ax+y
(Ax)y = Ax*y
And Square-root of x is equal to x(1/2)
So this forumula is equivalent to:
(x^10)^1/2 * (x^4)^1/2
= x^(10/2) * x^(4/2)
= x^5 * x^2
= x^(5 + 2)
= X^7
√x10×√x4=√(x5)2×√(x2)2=x5×x2=x×(5+2)=x7
Second way
√a×√b=√ab
√x10×√x4=√x10×x4=√x14=√(x7)2=x7
.In the form of a formula this is:
√x10×√x4
Some things to consider:
Ax * Ay = Ax+y
(Ax)y = Ax*y
And Square-root of x is equal to x(1/2)
So this forumula is equivalent to:
(x^10)^1/2 * (x^4)^1/2
= x^(10/2) * x^(4/2)
= x^5 * x^2
= x^(5 + 2)
= X^7