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simplify the expression "the square root of x^10 times the square root of x^4" completely

 Jun 23, 2015

Best Answer 

 #2
avatar+427 
+5

In the form of a formula this is:

 x10×x4

 

Some things to consider:

Ax * Ay = Ax+y

(Ax)y = Ax*y

And Square-root of x is equal to x(1/2)

 

So this forumula is equivalent to:

(x^10)^1/2 * (x^4)^1/2

= x^(10/2) * x^(4/2)

= x^5 * x^2

= x^(5 + 2)

= X^7

 Jun 23, 2015
 #1
avatar
+5

x10×x4=(x5)2×(x2)2=x5×x2=x×(5+2)=x7

Second way

a×b=ab

x10×x4=x10×x4=x14=(x7)2=x7

.
 Jun 23, 2015
 #2
avatar+427 
+5
Best Answer

In the form of a formula this is:

 x10×x4

 

Some things to consider:

Ax * Ay = Ax+y

(Ax)y = Ax*y

And Square-root of x is equal to x(1/2)

 

So this forumula is equivalent to:

(x^10)^1/2 * (x^4)^1/2

= x^(10/2) * x^(4/2)

= x^5 * x^2

= x^(5 + 2)

= X^7

Sir-Emo-Chappington Jun 23, 2015

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