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$${\frac{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{16}}}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

 Mar 11, 2015

Best Answer 

 #2
avatar+118609 
+5

$${\frac{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{16}}}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

$${\frac{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

$${\frac{{\mathtt{7}}}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

 

$$\left({\frac{{\mathtt{7}}}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}{\mathtt{\,\times\,}}{\frac{\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{2}}}}\right)}{\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{2}}}}\right)}}\right)$$

 

$$\\\frac{35+7\sqrt{2}}{25-2}\\\\
\frac{35+7\sqrt{2}}{23}\\\\$$

.
 Mar 11, 2015
 #1
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0

$${\frac{\left({\mathtt{7}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}} = {\mathtt{1.952\: \!151\: \!953\: \!765\: \!724\: \!6}}$$

.
 Mar 11, 2015
 #2
avatar+118609 
+5
Best Answer

$${\frac{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{16}}}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

$${\frac{\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}\right)}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

$${\frac{{\mathtt{7}}}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}$$

 

$$\left({\frac{{\mathtt{7}}}{\left({\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\right)}}{\mathtt{\,\times\,}}{\frac{\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{2}}}}\right)}{\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{2}}}}\right)}}\right)$$

 

$$\\\frac{35+7\sqrt{2}}{25-2}\\\\
\frac{35+7\sqrt{2}}{23}\\\\$$

Melody Mar 11, 2015

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