I used the web2.0calculator
Here's the answer
$$\left({\frac{\left(\left(\left(\left(\left({\mathtt{56}}{\mathtt{\,\times\,}}{\mathtt{p9r3}}\right){\mathtt{\,\times\,}}{\mathtt{pr}}\right){\mathtt{\,\times\,}}{\mathtt{x2}}\right){\mathtt{\,\times\,}}{\mathtt{y4}}\right){\mathtt{\,\times\,}}{\mathtt{y620p14qr7}}\right)}{{\mathtt{5}}}}\right)$$
Edit: Nevermind, it's not fully simplified