(3x + 2)^2

(3x + 2)^{2}

= (3x + 2)(3x + 2)

Multiply each term in the first set of parenthesees by each term in the second set of parenthesees and add these products together.

= (3x)(3x) + (3x)(2) + (2)(3x) + (2)(2)

= 9x^{2} + 6x + 6x + 4

= 9x^{2} + 12x + 4