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Simplify. Write the answer with all variables in the numerator.

 

xx (x^2) ^-2 (x^2)(x^-3y^0)^5

 Jan 12, 2016

Best Answer 

 #6
avatar+537 
+5

what's wrong with it being in the numerator?

 Jan 12, 2016
 #1
avatar
+5

Simplify the following:
(x x x^2 (y^0/x^3)^5)/((x^2)^2)

x x = x^2:
(x^2 x^2 (y^0/x^3)^5)/((x^2)^2)

Multiply exponents. (x^2)^2 = x^(2×2):
(x^2 x^2 (y^0/x^3)^5)/(x^(2×2))

2×2  =  4:
(x^2 x^2 (y^0/x^3)^5)/(x^4)

y^0 = 1:
(x^2 x^2 (1/x^3)^5)/(x^4)

Multiply exponents. (x^(-3))^5 = x^(-3×5):
(x^2 x^2 x^(-3×5))/x^4

-3×5  =  -15:
(x^2 x^2 x^-15)/x^4

Combine powers. x^2/x^15 = x^(2-15):
(x^2 x^2-15)/x^4

2-15 = -13:
(x^2 x^-13)/x^4

Combine powers. x^2/(x^13 x^4) = x^(2-4-13):
x^2-4-13

2-4-13 = -15:
Answer: | x^-15

 Jan 12, 2016
 #2
avatar+1832 
+5

 

hope this helpful 

 Jan 12, 2016
 #3
avatar
+5

1-They are exactly the same.

2- Your question says "Write the answer with all variables in the numerator."

 Jan 12, 2016
 #4
avatar+1832 
+5

Guest You are right 

 Jan 12, 2016
 #5
avatar+1832 
+5

 

 

 

........ 

.
 Jan 12, 2016
 #6
avatar+537 
+5
Best Answer

what's wrong with it being in the numerator?

KatieLeigh Jan 12, 2016
 #7
avatar+118667 
+5

Nothing is wrong with leaving it in the numerator KatieLeigh,

BUT normally it would be rewritten as xvxvxv first presented it.  I would consider it more 'simple' if it is written as a fraction.

 

Guest was right though - the question specifically asked for it all to be left in the numerator :)

 Jan 13, 2016
 #8
avatar+537 
0

oh okay. i just didn't understand how to get it there

 Jan 13, 2016

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