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simplify x^2-9x+1

 Apr 16, 2015

Best Answer 

 #1
avatar+130516 
+5

There's nothing to "simplify".....this won't factor, but we can use the onsite solver (with a little help from the quadratic formula) to find the solutions......they will be "real" ones....

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{77}}}}{\mathtt{\,-\,}}{\mathtt{9}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{77}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.112\: \!517\: \!806\: \!303\: \!939}}\\
{\mathtt{x}} = {\mathtt{8.887\: \!482\: \!193\: \!696\: \!061}}\\
\end{array} \right\}$$

 

  

 Apr 16, 2015
 #1
avatar+130516 
+5
Best Answer

There's nothing to "simplify".....this won't factor, but we can use the onsite solver (with a little help from the quadratic formula) to find the solutions......they will be "real" ones....

 

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{77}}}}{\mathtt{\,-\,}}{\mathtt{9}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{77}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.112\: \!517\: \!806\: \!303\: \!939}}\\
{\mathtt{x}} = {\mathtt{8.887\: \!482\: \!193\: \!696\: \!061}}\\
\end{array} \right\}$$

 

  

CPhill Apr 16, 2015

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