SIMPLIFY$${\frac{{\mathtt{1}}}{{\mathtt{p}}}}$$ - $${\frac{{\mathtt{1}}}{{{\mathtt{p}}}^{{\mathtt{2}}}}}$$
Good work anon
but it would have been quicker if you had made p^2 the common denominator in the first place. :)
$$\frac {1}{p}-\frac{1}{p^2}$$
$$\frac{p^2-p}{p^3}$$
$$\frac{p(p-1)}{(p)(p^2}$$
$$\frac{p-1}{p^2}$$
