$$(6a^2+5a+10)-(4a^2+6a+12)$$
There is an invisable 1 between the minus sign and the bracket.
Everything inside the bracket muct be multipled by -1
$$(6a^2+5a+10)\textcolor[rgb]{1,0,0}{-1}(4a^2+6a+12)\\\\
=(6a^2+5a+10)-4a^2-6a-12\\\\
=6a^2+5a+10-4a^2-6a-12\\\\
=6a^2-4a^2+5a-6a+10-12\\\\
=2a^2-1a-2\\\\
=2a^2-a-2\\\\$$
$$(6a^2+5a+10)-(4a^2+6a+12)$$
There is an invisable 1 between the minus sign and the bracket.
Everything inside the bracket muct be multipled by -1
$$(6a^2+5a+10)\textcolor[rgb]{1,0,0}{-1}(4a^2+6a+12)\\\\
=(6a^2+5a+10)-4a^2-6a-12\\\\
=6a^2+5a+10-4a^2-6a-12\\\\
=6a^2-4a^2+5a-6a+10-12\\\\
=2a^2-1a-2\\\\
=2a^2-a-2\\\\$$