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2X^-3Y^2*(2Y)^-2/2X^-4Y^2

 

Simplify

 Apr 19, 2015

Best Answer 

 #1
avatar+118667 
+5

$$\\\frac{2X^{-3}Y^2*(2Y)^{-2}}{2X^{-4}Y^2}\\\\
=\frac{\not{2}X^{(-3--4)}Y^2*2^{-2}Y^{(-2-2)}}{\not{2}}\\\\
=\frac{X^{1}Y^2*2^{-2}Y^{-4}}{1}\\\\
=\frac{X^{1}*2^{-2}Y^{(2-4)}}{1}\\\\
=\frac{X*2^{(-2)}Y^{(-2)}}{1}\\\\
=\frac{X}{1*2^{(+2)}Y^{(+2)}}\\\\
=\frac{X}{4Y^{2}}\\\\$$

.
 Apr 20, 2015
 #1
avatar+118667 
+5
Best Answer

$$\\\frac{2X^{-3}Y^2*(2Y)^{-2}}{2X^{-4}Y^2}\\\\
=\frac{\not{2}X^{(-3--4)}Y^2*2^{-2}Y^{(-2-2)}}{\not{2}}\\\\
=\frac{X^{1}Y^2*2^{-2}Y^{-4}}{1}\\\\
=\frac{X^{1}*2^{-2}Y^{(2-4)}}{1}\\\\
=\frac{X*2^{(-2)}Y^{(-2)}}{1}\\\\
=\frac{X}{1*2^{(+2)}Y^{(+2)}}\\\\
=\frac{X}{4Y^{2}}\\\\$$

Melody Apr 20, 2015

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