First compute the denom ....I will ASSUME both of the right terms are in the denominator thusly:
(1+i) / ( (2-i)(3+i) )
(2-i)(3+i) =
6 + 2i -3i - i^2
6 - i +1
7 - i
now you have
(1+i) / (7-i) multiply by ( 7+i) / (7+i) to get
(6+8i)/ 50 which reduces to (3+4i)/25