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How do you simplify Fractions similar to this?

((1/x^4)*(x^8))/1^2

Please give an explanation <3

 Jun 7, 2017

Best Answer 

 #1
avatar+9460 
+2

\(\frac{\frac1{x^4}*x^8}{1^2}\)                   1^2 = 1

 

\(=\frac{\frac1{x^4}*x^8}{1}\)              Any number divided by 1 equals the  original number.

 

\(=\frac1{x^4}*x^8\)           Multiply straight across.

 

\(=\frac{x^8}{x^4}\)                    Use the exponent rule that says:    \(\frac{x^a}{x^b}=x^{a-b}\)

 

\(=x^{8-4} \\~\\ =x^4\)

 Jun 7, 2017
 #1
avatar+9460 
+2
Best Answer

\(\frac{\frac1{x^4}*x^8}{1^2}\)                   1^2 = 1

 

\(=\frac{\frac1{x^4}*x^8}{1}\)              Any number divided by 1 equals the  original number.

 

\(=\frac1{x^4}*x^8\)           Multiply straight across.

 

\(=\frac{x^8}{x^4}\)                    Use the exponent rule that says:    \(\frac{x^a}{x^b}=x^{a-b}\)

 

\(=x^{8-4} \\~\\ =x^4\)

hectictar Jun 7, 2017

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