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3x^3y^-2/xy^3

 Jan 7, 2021

Best Answer 

 #1
avatar+188 
+2

We can bring the y^-2 down to the denominator and divide by the x to get 3x^2/y^5

:D

 Jan 7, 2021
 #1
avatar+188 
+2
Best Answer

We can bring the y^-2 down to the denominator and divide by the x to get 3x^2/y^5

:D

AvenJohn Jan 7, 2021
 #2
avatar
0

Using algebra, we can see after subtracting a few numbers, we notice there are 10 numbers, therefore there are 5 pairs and one number.

 

$1-2, 4-8, 16-32, 64-128, 256-512, 1024$

 

using normal subtraction 

We get 

683

 Jan 8, 2021
 #3
avatar
0
  1. Oh my god I answered on the wrong question blush
 Jan 8, 2021
 #4
avatar+188 
+2

LOL!

AvenJohn  Jan 8, 2021

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