Simplify \(\dfrac{\sqrt[3]{32} \cdot \sqrt{128}}{\sqrt[6]{16}}\)
25/3 * 27/2 / 24/6
= 2 10/6 + 21/6 - 4/6 = 2 27/6 = 24 +1/2
= 16 sqrt 2
just use fractional exponents and then bash :P
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