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(2n)!/(2n-3)

 
Guest Jun 18, 2017
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(2n)! / (2n -3) =

 

[2n * (2n-1) *(2n -2) * (2n -3) * ......* 1]  / [ (2n-3) ] =

 

2n * (2n - 1) * (2n -2) * (2n - 4) * (2n - 5) *  .... *  3 * 2 * 1 

 

 

 

cool cool cool

 
CPhill  Jun 18, 2017
edited by CPhill  Jun 18, 2017

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