Simplify

(3x2y3)(2xy2)2

____________

       -2x2y

$\Large \frac{(3x^2y^3)(2xy^2)^2}{-2x^2y}=\frac{(3x^2y^3)(4x^2y^4)}{-2x^2y}=-6x^2y^6$

  !

$\dfrac{\left(3x^2y^3\right)\left(2xy^2\right)^2}{-2x^2y}\\ =\dfrac{\left(3\cdot 2\right)\cdot\left(x^2\cdot x^2\right)\cdot\left(y^3\cdot y^4\right)}{-2x^2y}\\ =\dfrac{6x^4y^7}{-2x^2y}\\ =\left(\dfrac{6}{-2}\right)\left(\dfrac{x^4}{x^2}\right)\left(\dfrac{y^7}{y}\right)\\ =-3x^2y^6$

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