We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
234
2
avatar

\({3^{-1} + 4^{-1} \over 6^{-1}}\)

so i know i can get rid of the negatives by:

\({6^{1} \over 3^{1} + 4^{1}}\)

then i got:

\({6 \over 7}\)

but the right answer is \({7 \over 2}\), what did i do wrong?

 Jul 4, 2018
 #1
avatar
+1

3^-1 + 4^-1 means =1/3 + 1/4. But 6^-1 also means 1/6, so:

 

[1/3+1/4] / 1/6=7/12 x 6/1=42/12 =7/2

 Jul 4, 2018
 #2
avatar+1697 
+3

Do this:

 

\(\dfrac{3^{-1}+4^{-1}}{6^{-1}} \hspace{.1cm} =\dfrac {\dfrac {1}{3}+\dfrac {1}{4}}{6^{-1}}\\ \\\:\\ \hspace{.1cm} =\dfrac {\dfrac {7}{12}}{6^{-1}} \hspace{.1cm} =\dfrac {7}{6^{-1}\cdot 12}\\ \\\:\\ \hspace{.1cm}=\dfrac {7}{2}\\\)

 

 

GA

 Jul 4, 2018

12 Online Users