\({3^{-1} + 4^{-1} \over 6^{-1}}\)
so i know i can get rid of the negatives by:
\({6^{1} \over 3^{1} + 4^{1}}\)
then i got:
\({6 \over 7}\)
but the right answer is \({7 \over 2}\), what did i do wrong?
3^-1 + 4^-1 means =1/3 + 1/4. But 6^-1 also means 1/6, so:
[1/3+1/4] / 1/6=7/12 x 6/1=42/12 =7/2
Do this:
\(\dfrac{3^{-1}+4^{-1}}{6^{-1}} \hspace{.1cm} =\dfrac {\dfrac {1}{3}+\dfrac {1}{4}}{6^{-1}}\\ \\\:\\ \hspace{.1cm} =\dfrac {\dfrac {7}{12}}{6^{-1}} \hspace{.1cm} =\dfrac {7}{6^{-1}\cdot 12}\\ \\\:\\ \hspace{.1cm}=\dfrac {7}{2}\\\)
GA
