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\({3^{-1} + 4^{-1} \over 6^{-1}}\)

so i know i can get rid of the negatives by:

\({6^{1} \over 3^{1} + 4^{1}}\)

then i got:

\({6 \over 7}\)

but the right answer is \({7 \over 2}\), what did i do wrong?

Guest Jul 4, 2018