sin-1/cos-1

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sin-1/cos-1

Guest Jul 14, 2014

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Best Answer

Question does not really make sense but

For $$0<\alpha<90\: degrees$$

$$\dfrac{sin^{-1}(\frac{x}{y})}{cos^{-1}(\frac{x}{y})}=\dfrac{90-\alpha}{\alpha}$$

Melody Jul 15, 2014

Melody · Answer 1 · 2014-07-15T05:54:20

Question does not really make sense but

For $$0<\alpha<90\: degrees$$

$$\dfrac{sin^{-1}(\frac{x}{y})}{cos^{-1}(\frac{x}{y})}=\dfrac{90-\alpha}{\alpha}$$