〖sin〗^(-1) [〖ln [sech⁡〖(5<30)+cos⁡j5 〗 ]〗⁡〖+cos⁡〖(3-j5)〗〗/tan⁡[ln⁡csc⁡(2-j6) ] ]

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〖sin〗^(-1) [〖ln [sech⁡〖(5<30°)+cos⁡j5 〗 ]〗⁡〖+cos⁡〖(3-j5)〗〗/tan⁡[ln⁡csc⁡(2-j6) ] ]

Guest Jul 13, 2020

Melody · Answer 1 · 2020-07-13T06:54:56

I am confused by the question.

what does 5<30degrees mean ?

does j signify imaginary units? (I assume it does)

〖sin〗^(-1) [〖ln [sech⁡〖(5<30)+cos⁡j5 〗 ]〗⁡〖+cos⁡〖(3-j5)〗 〗/tan⁡[ln⁡csc⁡(2-j6) ] ]