i believe we have
sin^(2)x + 5 sinx - 3= 0 we could make a substitution and use the quadratic formula, but I prefer a graphical approach
Here it is......https://www.desmos.com/calculator/fxereunfe1
This graph is periodic and solutions occur at about 32.8 ± n360 degrees ... and at 147.2 ± n360 degrees {where n is an integer}
i believe we have
sin^(2)x + 5 sinx - 3= 0 we could make a substitution and use the quadratic formula, but I prefer a graphical approach
Here it is......https://www.desmos.com/calculator/fxereunfe1
This graph is periodic and solutions occur at about 32.8 ± n360 degrees ... and at 147.2 ± n360 degrees {where n is an integer}