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Rewrite sin3x with cos and sin. I just want to know how to apply the double angle formula with the 3.

Guest Apr 3, 2017
 #1
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sin 3x  =

 

sin (2x + x)  =

 

sin2xcosx + sinxcos2x =

 

2sinxcosxcosx + sinx (2cos^2x - 1) =

 

2sinxcos^2x + 2sinxcos^2x -  sinx =

 

4sinxcos^2x - sinx 

 

sinx ( 4cos^2x - 1 )

 

Note......other answers are possible....!!!

 

 

cool cool cool

CPhill  Apr 3, 2017

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