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sin^4a+cos^4a=

 May 2, 2015

Best Answer 

 #1
avatar+130516 
+5

We have

(sin^2a x sin^2a + cos^2a x cos^2a) =

sin^2a x sin^2a + (1- sin^2a) x (1- sin^2a) =

sin^2a x sin^2a + 1 - 2sin^2a + sin^2a x sin^2a  =

2 sin^4a + 1 - 2 sin^2a =

2sin^4a - 2sin^2a + 1

{Note.....other answers are possible}

 

  

 May 2, 2015
 #1
avatar+130516 
+5
Best Answer

We have

(sin^2a x sin^2a + cos^2a x cos^2a) =

sin^2a x sin^2a + (1- sin^2a) x (1- sin^2a) =

sin^2a x sin^2a + 1 - 2sin^2a + sin^2a x sin^2a  =

2 sin^4a + 1 - 2 sin^2a =

2sin^4a - 2sin^2a + 1

{Note.....other answers are possible}

 

  

CPhill May 2, 2015

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