sin(π/6)*[√4] + (3!)^2 - (46,656)^(1/3)

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Uh... whats sin(π/6)*[√4] + (3!)^2 - (46,656)^(1/3)?

Guest Apr 16, 2015

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Best Answer

+130511

+5

sin(π/6)*[√4] + (3!)^2 - (46,656)^(1/3)

(1/2) * 2 + 6^2 - 36 =

1 + 36 - 36 =

wait for it......!!!

1

CPhill Apr 16, 2015

1⁺⁰ Answers

+130511

+5

Best Answer

sin(π/6)*[√4] + (3!)^2 - (46,656)^(1/3)

(1/2) * 2 + 6^2 - 36 =

1 + 36 - 36 =

wait for it......!!!

1

CPhill Apr 16, 2015

2 Online Users