in the construction of a certain road, an overpass must be planned 10 m over a railroad track. The rise in the road is to be uniform and the start 190 m from the track. What will be the measure of the angle of rise of the overpass?
+118723 
$$tan\theta =\frac{10}{190}$$
$$\theta=tan^{-1}\left(\frac{10}{190}\right)$$
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{10}}}{{\mathtt{190}}}}\right)} = {\mathtt{3.012\: \!787\: \!504\: \!183^{\circ}}}$$
approximately 3 degrees.
+118723
$$tan\theta =\frac{10}{190}$$
$$\theta=tan^{-1}\left(\frac{10}{190}\right)$$
$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{10}}}{{\mathtt{190}}}}\right)} = {\mathtt{3.012\: \!787\: \!504\: \!183^{\circ}}}$$
approximately 3 degrees.
