sin tan cos

im a banana!!!!!!!!!!!!!!!

sin a =  tan a     then a =0 degrees     then cos 0  = 1

If sin A = tan A  ....then

sin A  = sin A / cos A      multiply both sides by cos A

sin A cos A  = sin A     divide both sides by sin A

cos A  = sin A / sin A

cos A  = 1

And   A  = 0°

I just realized that I committed a cardinal sin on this one....I cannot divide by sin A....since A  = 0°

Here's a correct approach :

sin A  = tan A

sin A  = sin A / cos A

sin A - sin A/ cos A   = 0     factor out sin A

sin A [ 1 - 1/cos A]  = 0

sin A  [ 1 - sec A ]  = 0

So either   sin A  = 0     in which case A = 0°   or   sec A  = 1......which further confirms that A = 0°  .....and cos A  = cos 0°  = 1