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sin0=17/37 what is sec0

 Jan 25, 2017
 #1
avatar+30 
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I assume that by 0 you mean theta.

 

First you'd need to find the cosine of theta (because secant is the reciprocal of cosine). We can do this with right triangle trig. Sine is opposite over hypotenuse, so draw a right triangle, pick an angle and call it theta, and then lable the opposite side 17 and the hypotenuse 37. You can use the pythagorean theorem to get the measure of the third side.

 

172 + b= 372

289 + b2 = 1369

b2 = 1080

b = 6*sqrt(30)

 

The cosine of theta is 6*sqrt(30)/37. Therefore, the secant of theta is 37/6*sqrt(30). Apparently you're not supposed to leave radicals in the denominator of a fraction, so you'd multiply by sqrt(30)/sqrt(30) to get 37*sqrt(30)/6*30, which is 37*sqrt(30)/180.

 Jan 25, 2017
 #2
avatar+118689 
0

thanks      maths not math   wink

 Jan 25, 2017

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