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Sin2(280°+2Π) x Log(Cos85°) + tanΠ\2 - √567=?

 Jun 6, 2015

Best Answer 

 #1
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Sin2(280+2π)×Log(Cos85)+tan(π/2)567Sin2(280)×Log(Cos85)+1567

 

sin360(280)2×log10(cos360(85))+1567=23.8395118060089477

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 Jun 7, 2015
 #1
avatar+118696 
+5
Best Answer

Sin2(280+2π)×Log(Cos85)+tan(π/2)567Sin2(280)×Log(Cos85)+1567

 

sin360(280)2×log10(cos360(85))+1567=23.8395118060089477

Melody Jun 7, 2015

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