Sin2(280°+2Π) x Log(Cos85°) + tanΠ\2 - √567=?

$$\\Sin^2(280+2\pi) \times Log(Cos85) + tan(\pi/2) - \sqrt{567}\\ Sin^2(280) \times Log(Cos85) + 1 - \sqrt{567}\\$$

$${\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{280}}^\circ\right)}}^{\,{\mathtt{2}}}{\mathtt{\,\times\,}}{log}_{10}\left(\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{85}}^\circ\right)}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{1}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{567}}}} = -{\mathtt{23.839\: \!511\: \!806\: \!008\: \!947\: \!7}}$$