sin2 (pie/7) + cos2 (pie/7)=

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sin^{2_{(pie/7) +}}_cos²^_(pie/7)=

Guest Mar 29, 2015

+118724

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Best Answer

I think that you mean

$$\\sin^2\;\frac{\pi}{7}+cos^2\;\frac{\pi}{7}\\\\
$Well this is very simple because $\\\\
sin^2\theta +cos^2\theta = 1\qquad ALWAYS$$

Melody Mar 29, 2015

Melody · Answer 1 · 2015-03-29T06:40:52

I think that you mean

$$\\sin^2\;\frac{\pi}{7}+cos^2\;\frac{\pi}{7}\\\\
$Well this is very simple because $\\\\
sin^2\theta +cos^2\theta = 1\qquad ALWAYS$$