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18 sin b = 8 sin 110 ?

Guest May 2, 2017
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 #1
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I'm assuming you want to solve for b.

\(18sinb = 8 sin110\)

\(sin b = \frac{8}{18}sin110\)

\(sinb = \frac{4}{9} sin110\)

\(arcsin (sin b) = arc sin( \frac{4}{9}sin110)\)

b = -0.0197

JonathanB  May 2, 2017
 #2
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18 sin b = 8 sin 110

sin b = 4/9 * sin 110

b = 24.69 degrees.

sin 110 is assumed sin 110deg.

MaxWong  May 2, 2017

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