18 sin b = 8 sin 110 ?
I'm assuming you want to solve for b.
\(18sinb = 8 sin110\)
\(sin b = \frac{8}{18}sin110\)
\(sinb = \frac{4}{9} sin110\)
\(arcsin (sin b) = arc sin( \frac{4}{9}sin110)\)
b = -0.0197
18 sin b = 8 sin 110
sin b = 4/9 * sin 110
b = 24.69 degrees.
sin 110 is assumed sin 110deg.
