+0  
 
0
157
1
avatar

sinC/20 = sin65/19, how it gets to C=arcsin(20sin65/19)=73

off-topic
Guest May 30, 2017

Best Answer 

 #1
avatar+5541 
+2

\(\frac{\sin C}{20}=\frac{\sin 65^{\circ}}{19}\)

 

Multiply both sides of the equation by 20.

\(\sin C=20\,*\,\frac{\sin 65^{\circ}}{19} \\~\\ \sin C = \frac{20\sin 65^{\circ}}{19}\)

 

Take the arcsin of both sides of the equation.

\( C = \arcsin(\frac{20\sin 65^{\circ}}{19})\)

 

So...putting this into a calculator gives us

\(C\approx72.556^{\circ}\)

hectictar  May 30, 2017
Sort: 

1+0 Answers

 #1
avatar+5541 
+2
Best Answer

\(\frac{\sin C}{20}=\frac{\sin 65^{\circ}}{19}\)

 

Multiply both sides of the equation by 20.

\(\sin C=20\,*\,\frac{\sin 65^{\circ}}{19} \\~\\ \sin C = \frac{20\sin 65^{\circ}}{19}\)

 

Take the arcsin of both sides of the equation.

\( C = \arcsin(\frac{20\sin 65^{\circ}}{19})\)

 

So...putting this into a calculator gives us

\(C\approx72.556^{\circ}\)

hectictar  May 30, 2017

3 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details