#1**+2 **

\(\frac{\sin C}{20}=\frac{\sin 65^{\circ}}{19}\)

Multiply both sides of the equation by 20.

\(\sin C=20\,*\,\frac{\sin 65^{\circ}}{19} \\~\\ \sin C = \frac{20\sin 65^{\circ}}{19}\)

Take the arcsin of both sides of the equation.

\( C = \arcsin(\frac{20\sin 65^{\circ}}{19})\)

So...putting this into a calculator gives us

\(C\approx72.556^{\circ}\)

hectictar
May 30, 2017

#1**+2 **

Best Answer

\(\frac{\sin C}{20}=\frac{\sin 65^{\circ}}{19}\)

Multiply both sides of the equation by 20.

\(\sin C=20\,*\,\frac{\sin 65^{\circ}}{19} \\~\\ \sin C = \frac{20\sin 65^{\circ}}{19}\)

Take the arcsin of both sides of the equation.

\( C = \arcsin(\frac{20\sin 65^{\circ}}{19})\)

So...putting this into a calculator gives us

\(C\approx72.556^{\circ}\)

hectictar
May 30, 2017