right-angled Triangle DEF qith e=18.3 and angle beta = 72 degrees. please calculate missing legs and angles. thank you in advance :D
+130518 I'm assuming that beta is the angle oposite "e".....[thus, "e" is a leg]
The other non-right angle = 90 - 72 = 18 degrees
And we can find the length of the other leg , x , using the Law of Sines....so we have
x / sin 18 = 18.3 / sin 72 → x = (18.3)(sin 18) / sin(72) = about 5.95
The hypotenuse = sqrt(18.3^2 + 5.95^2) = about 19.24
