How to solve: 60 = 30 sin 60 (3-d) + 30 ?????? where d is the phase shift. Hope you can help.

y = a sin k(x-d) + c

Thanks.

60 = 30 sin 60 (3-d) + 30 subtract 30 from each side

30 = 30sin (180 - 60d) divide both sides by 30

1= sin (180 - 60d) the sine will = 1 at 90°

Therefore ..... 180 - 60d = 90 subtract 180 from each side

-60d = - 90 divide both sides by -60

d = 9/6 = 3/2