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How to solve: 60 = 30 sin 60 (3-d) + 30 ?????? where d is the phase shift.  Hope you can help.

 

y = a sin k(x-d) + c

 

Thanks.

Guest Aug 17, 2017
 #1
avatar+86859 
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 60 = 30 sin 60 (3-d) + 30   subtract 30 from each side

 

30  = 30sin (180 - 60d)       divide both sides by 30

 

1=  sin (180 - 60d)         the sine will = 1 at 90°

 

Therefore .....    180 - 60d   = 90     subtract 180 from each side

 

-60d  = - 90     divide both sides by -60

 

d  = 9/6  =  3/2

 

 

cool cool cool

CPhill  Aug 17, 2017

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