l totally forgot to account for arcsin.
Sorry Wong.
You stated the general solution and that threw me for a loop.
But x= pi/2 was correct.
\(\sin X = 1\\ X = \arcsin 1 = \dfrac{\pi}{2}\\ \text{General solution:}X = \dfrac{\pi}{2} + 2n\pi\)
.l think you have some misunderstanding. x=0
Sin(0)=1
My proof: Unit Circle.
Try memorizing a unit circle. They have much needed utility in higher levels of math.
x=0 radians
l totally forgot to account for arcsin.
Sorry Wong.
You stated the general solution and that threw me for a loop.
But x= pi/2 was correct.
l should stop answering questions for tonight. Fatigue really messes with your sense of the UC. But that's no excuse. Thank you for the clarification. :D