slope

6x+3y-1=0

3y = -6x + 1

y = -2x + 1/3

The slope is -2, so the perpendicular slope line is the negative reciprocal, 1/2. 

=^._.^=

What is the slope of any line perpendicular to 6x+3y-1=0?

Hello Guest!

$6x+3y-1=0\\ y=-\frac{6}{3}x+\frac{1}{3}\\ y=-2x+\frac{1}{3}$

           m        n

$m_{perpendicular}=-\frac{1}{m}=-\frac{1}{-2}=\color{blue}\frac{1}{2}$

  !