Slope

What is the equation with points of (6,-8) and (3,-4) with a slope of -4/3

\(\large m=\frac{y_2-y_1}{x_2-x_1}\)

\(\large m=\frac{-4+8}{3-6}=-\frac{4}{3}\)

\(\large y=mx+n\)

\(n= y_1-m\times x_1\)

\(n= -8-(-\frac{4}{3})\times 6\)

\(\large n=0\)

\(\large y=mx+n\)

\(\large y=-\frac{4}{3}x+0\)

\(\large f(x)=y=-\frac{4}{3}x\)

  !

y=mx+b       where  m = -4/3  and point  6, -8

-8 = -4/3 (6) + b        solve for b

b = -8+4/3*6 = 0

y = -4/3 x + 0    or just    y= - 4/3 x