How can you find the eqauton of the line that is perpendicular and parallel to this line?
+129845 The slope of the given line = -8
A perpendicular line will have a negative reciprocal slope.....so....our line will have a slope = 1/8 = m
The equation is
y - y1 = m ( x - x1)
And using (-3, -5) for (x1, y1) we have
y - -5 = (1/8) (x - -3) simplify
y + 5 = (1/8)( x + 3)
y + 5 = (1/8)x + 3/8 subtract 5 from both sides
y = (1/8)x + 3/8 - 5
y = (1 /8)x + 3/8 - 40/8
y = (1/8) x - 37/8
A parallel line will have the same slope as the given line......so using the same idea as above
y - -5 = -8 (x - - 3)
y + 5 = -8(x + 3)
y + 5 = -8x - 24
y = -8x -29
